X^2-4x-0.8=0

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Solution for X^2-4x-0.8=0 equation:



X^2-4X-0.8=0
a = 1; b = -4; c = -0.8;
Δ = b2-4ac
Δ = -42-4·1·(-0.8)
Δ = 19.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{19.2}}{2*1}=\frac{4-\sqrt{19.2}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{19.2}}{2*1}=\frac{4+\sqrt{19.2}}{2} $

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